8y^2+105y+13=0

Solution for 8y^2+105y+13=0 equation:

8y^2+105y+13=0

a = 8; b = 105; c = +13;
Δ = b2-4ac
Δ = 1052-4·8·13
Δ = 10609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10609}=103$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(105)-103}{2*8}=\frac{-208}{16}
=-13
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(105)+103}{2*8}=\frac{-2}{16}
=-1/8
$